2026 MIT Integration Bee Finals: Two Clever Substitutions Unlock A Fourth-Root Integral
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YouTubeMagicMathMaster
2026 MIT Integration Bee Finals: Two Clever Substitutions Unlock A Fourth-Root Integral
A terrifying-looking integral from the 2026 MIT Integration Bee Finals, Problem 2, becomes surprisingly manageable after two perfectly chosen substitutions. First, u = (x+1)/(x-1), transforms the original fourth-root expression into a cleaner radical involving u^4−1. Then, t= (u^4−1)^(1/4)/u collapses the problem into a rational integral ...
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